A hyperdrive lets you travel its maximum range in seven
days, which is 168 hours. Travel time is linear with distance, so you will
use one day to travel a seventh of your hyperdrive range. For a class n
drive you will need n2 tons of fuel to travel the maximum range, except
for the class 8 hyperdrive which actually is a class 9 drive and therefore
uses 81 tons for a maximum range jump. The fuel consumption is linear with
the distance, using only integer amounts of fuel, so you will need e.~g.
#math161#⌈#tex2html_wrap_inline2078#⌉ tons of fuel to travel half the maximum drive
range. The only difference between the civil and military versions of a drive
is the weight of the drive and the type of fuel used.
The relation between jump cost c [t], jump time t [h], ship mass
m [t] and jump distance d [lj] can be expressed a little more exact to
give you a few numbers to crunch. Here the equations:
#math162#
|
| c = #tex2html_wrap_indisplay2085##tex2html_wrap_indisplay2086##tex2html_wrap_indisplay2087# |
, *1cm#tex2html_wrap_indisplay2088#
|
(5) |
If you set the time to the maximum 168 h in the second
equation you can calculate the maximum range of the drive of a given class in
a given ship. If you do this for the class 8 drive in a Panther or Boa you
get inconsistencies. From table #tab:ships#264> you can see that the class 8
drive behaves like a class 9 drive in the Panther and like a class 7.79 drive
in the Boa. I hope this indicates a mistake in the table. The maximum ranges
for the Lynx Bulk Carrier and the Long Range Cruiser are calculated as if the
class 8 drive were actually class 9 drive. I don't know whether these ships
can carry hyperdrives at all.